Grasp Maths

Year 10

Set notation and Venn diagrams

Use set notation (∪\cup, ∩\cap, ∈\in, ⊂\subset, ∅\emptyset, A′A') and Venn diagrams to represent and solve probability problems involving unions, intersections, and complements.

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Lesson overview

Statistics — sets and probability

A **set** is a collection of distinct objects. We use specific notation to describe relationships between sets: - a∈Aa \in A means 'aa is an **element** of AA' - A∪BA \cup B means 'AA **union** BB' — everything in AA or BB or both - A∩BA \cap B means 'AA **intersection** BB' — only what is in both AA **and** BB - A′A' (or AcA^c) means the **complement** of AA — everything NOT in AA - ∅\emptyset is the **empty set** - A⊂BA \subset B means 'AA is a **subset** of BB' **Venn diagrams** represent sets visually: a rectangle (the universal set ξ\xi) containing overlapping circles. The overlap shows A∩BA \cap B, and the total covered area shows A∪BA \cup B. For probability: P(A∪B)=P(A)+P(B)−P(A∩B)P(A \cup B) = P(A) + P(B) - P(A \cap B)

Understanding Venn diagram regions

In a Venn diagram with sets AA and BB: the overlap is A∩BA \cap B, the total covered area is A∪BA \cup B, and everything outside AA is A′A'.

A∩BA \cap Bboth

intersection

A∪BA \cup Beither or both

union

A′A'not in A

complement

∅\emptysetnothing

empty set

Intersection = AND, Union = OR, Complement = NOT.

Using set notation for probability

If P(A)=0.6P(A) = 0.6, P(B)=0.4P(B) = 0.4, and P(A∩B)=0.2P(A \cap B) = 0.2, then P(A∪B)=0.6+0.4−0.2=0.8P(A \cup B) = 0.6 + 0.4 - 0.2 = 0.8.

We subtract the intersection so we don't double-count.

Complement rule

The probability of NOT AA is P(A′)=1−P(A)P(A') = 1 - P(A). If P(A)=0.3P(A) = 0.3, then P(A′)=0.7P(A') = 0.7.

Venn diagram: $A$ and $A'$$A$$A'$

P(A)+P(A′)=1P(A) + P(A') = 1 always.

Worked example

In a class of 3030 students, 1818 study French (FF) and 1414 study Spanish (SS). 66 study both. A student is chosen at random. Find the probability they study French or Spanish.

  1. n(F)=18n(F) = 18, n(S)=14n(S) = 14, n(F∩S)=6n(F \cap S) = 6, total =30= 30.
  2. Using the formula: n(F∪S)=n(F)+n(S)−n(F∩S)n(F \cup S) = n(F) + n(S) - n(F \cap S).
  3. n(F∪S)=18+14−6=26n(F \cup S) = 18 + 14 - 6 = 26.
  4. P(F∪S)=2630=1315P(F \cup S) = \dfrac{26}{30} = \dfrac{13}{15}.

Try it

Identify what each symbol means, then use the appropriate formula.

Question 1

If A={1,2,3,4}A = \{1, 2, 3, 4\} and B={3,4,5,6}B = \{3, 4, 5, 6\}, what is A∩BA \cap B?

Question 2

If P(A)=0.7P(A) = 0.7, what is P(A′)P(A')?

Question 3

If P(A)=0.5P(A) = 0.5, P(B)=0.4P(B) = 0.4, and P(A∩B)=0.2P(A \cap B) = 0.2, what is P(A∪B)P(A \cup B)?

Question 4

What does the symbol ∅\emptyset represent?

Question 5

If A⊂BA \subset B, which statement is true?

Common mistakes

Watch for these when working through the lesson.

  • Adding P(A)+P(B)P(A) + P(B) without subtracting P(A∩B)P(A \cap B) — this double-counts the overlap.
  • Confusing ∪\cup (union, OR) with ∩\cap (intersection, AND).
  • Forgetting that P(A′)=1−P(A)P(A') = 1 - P(A) is often the quickest route to an answer.

Related topics

These ideas fit closely with this lesson.

  • Probabilities of combined events.
  • Tree diagrams and conditional probability.
  • Sample space diagrams.

Practice next

Independent practice will plug in here

This lesson builds the understanding first. Deeper adaptive practice can sit here later.