Grasp Maths

Year 10

Surds and exact form

Simplify surds using the product rule, expand brackets containing surds, and rationalise the denominator to express answers in exact form.

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Lesson overview

Number - surds and exact values

A surd is the root of a number that cannot be simplified to remove the radical sign. Surds allow us to express exact values rather than decimals. For example, 2\sqrt{2} is a surd, but 4=2\sqrt{4} = 2 is not. We can simplify surds using the product rule: a×b=ab\sqrt{a} \times \sqrt{b} = \sqrt{ab}. We can also rationalise the denominator to remove surds from the bottom of a fraction: 1n=nn\frac{1}{\sqrt{n}} = \frac{\sqrt{n}}{n}. Working with surds is essential in GCSE maths because many exact answers are expressed as surds.

Simplifying surds

Simplify 12\sqrt{12} and 18\sqrt{18}.

Find the largest square number that divides the number under the surd. Use the product rule to split it.

Multiplying surds

Calculate 2×8\sqrt{2} \times \sqrt{8}.

Multiply under the surd sign, then simplify the result.

Rationalising the denominator

Rationalise 13\frac{1}{\sqrt{3}}.

Multiply numerator and denominator by the surd to remove it from the denominator.

Expanding brackets with surds

Expand (2+3)(1+3)(2 + \sqrt{3})(1 + \sqrt{3}).

Use FOIL (or distribution) carefully. Remember that a×a=a\sqrt{a} \times \sqrt{a} = a.

Worked example

Simplify 42\frac{4}{\sqrt{2}} and express in the form aba\sqrt{b} where aa and bb are integers.

  1. Identify that the denominator is a surd: 2\sqrt{2}.
  2. Multiply numerator and denominator by 2\sqrt{2} to rationalise.
  3. The numerator becomes 4×2=424 \times \sqrt{2} = 4\sqrt{2}.
  4. The denominator becomes 2×2=2\sqrt{2} \times \sqrt{2} = 2.
  5. Simplify the fraction: 422=22\frac{4\sqrt{2}}{2} = 2\sqrt{2}.
  6. The answer is 222\sqrt{2}, where a=2a = 2 and b=2b = 2.

Try it

Work through each question carefully. Check that you have simplified surds fully and rationalised denominators.

Question 1

Simplify 20\sqrt{20}.

💡 Find the largest square number that divides 20.

Question 2

Simplify 8+2\sqrt{8} + \sqrt{2}.

💡 Simplify 8\sqrt{8} first using the product rule, then add like surds.

Question 3

Rationalise 25\frac{2}{\sqrt{5}}.

💡 Multiply numerator and denominator by 5\sqrt{5}.

Question 4

Expand and simplify (2+1)2(\sqrt{2} + 1)^2.

💡 Use (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2. Remember 2×2=2\sqrt{2} \times \sqrt{2} = 2.

Question 5

Simplify 382\frac{3\sqrt{8}}{\sqrt{2}}.

💡 Simplify 8\sqrt{8} first, then divide by 2\sqrt{2}. Alternatively, use 82=82=4\frac{\sqrt{8}}{\sqrt{2}} = \sqrt{\frac{8}{2}} = \sqrt{4}.

Common mistakes

Watch for these when working through the lesson.

  • Forgetting to simplify surds fully. For example, leaving 12\sqrt{12} instead of simplifying to 232\sqrt{3}.
  • Adding surds that are not like terms. For example, 2+35\sqrt{2} + \sqrt{3} \neq \sqrt{5}. Only combine like surds such as 23+53=732\sqrt{3} + 5\sqrt{3} = 7\sqrt{3}.
  • Not rationalising the denominator. Always move surds from the bottom of a fraction to the top.
  • Expanding brackets incorrectly. Remember to use FOIL and be careful with a×a=a\sqrt{a} \times \sqrt{a} = a, not 2a2a.

Related topics

These ideas fit closely with this lesson.

  • Indices and powers
  • Quadratic equations and the quadratic formula
  • Pythagoras' theorem in 2D and 3D

Practice next

Independent practice will plug in here

This lesson builds the understanding first. Deeper adaptive practice can sit here later.