Grasp Maths

Year 9

Volume of cylinders, cones and spheres with formulae given

Calculate the volume of cylinders, cones and spheres using standard formulae, interpret 3D contexts, and solve multi-step volume problems.

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Lesson overview

Geometry — 3D shapes and volume

Volume measures how much space a 3D shape occupies. For a cylinder: V=πr2hV = \pi r^2 h (area of circular base times height). For a cone: V=13πr2hV = \frac{1}{3}\pi r^2 h (one-third of the cylinder volume with the same base and height). For a sphere: V=43πr3V = \frac{4}{3}\pi r^3. Always check units: if radius is in cm, volume is in cm3{cm}^{3}. If radius is in m, volume is in m3{m}^{3}.

Volume of a cylinder

Find the volume of a cylinder with radius 3 cm and height 8 cm.

3 cm8 cm

The volume is the area of the circular base (πr2{r}^{2}) times the height. Use a calculator for the final numerical answer.

Volume of a cone

Find the volume of a cone with radius 4 cm and height 9 cm.

9 cm4 cm

A cone is one-third the volume of a cylinder with the same base and height. Don't forget the 13\frac{1}{3}.

Volume of a sphere

Find the volume of a sphere with radius 5 cm.

5 cm

The formula uses r3r^3, not r2r^2. Remember the coefficient: 43\frac{4}{3}.

Worked example — a cylindrical can holds liquid

A cylindrical can has radius 4 cm and height 15 cm. How many millilitres does it hold? (1 cm3{cm}^{3} = 1 mL)

4 cm15 cm

A cylindrical can.

AnswerThe can holds approximately 754 mL
  1. Identify the shape and values: it's a cylinder with r = 4 cm and h = 15 cm.
  2. Use the formula for cylinder volume: V=πr2hV = \pi r^2 h.
  3. Substitute: V=π×42×15=π×16×15=240πV = \pi \times 4^2 \times 15 = \pi \times 16 \times 15 = 240\picm3.{cm}^{3}.
  4. Calculate: 240π753.98240\pi ≈ 753.98cm3.{cm}^{3}.
  5. Convert units: since 1 cm3{cm}^{3} = 1 mL, the can holds approximately 754 mL.

Try it

Use the correct formula for each shape. Always include units in your final answer.

Question 1

What is the formula for the volume of a cylinder?

💡 Volume = area of base (πr2{r}^{2}) × height.

Question 2

A cylinder has radius 2 cm and height 10 cm. Find the volume in cm3{cm}^{3} to 1 d.p.

💡 V=π×22×10=40π125.7V = \pi \times 2^2 \times 10 = 40\pi ≈ 125.7cm3.{cm}^{3}.

Question 3

A cone and a cylinder have the same radius and height. The cone's volume is:

💡 Volume of cone = 13πr2h\frac{1}{3}\pi r^2 h, which is exactly 13\frac{1}{3} of the cylinder's volume.

Question 4

A sphere has radius 3 cm. Find the volume in cm3{cm}^{3} to 1 d.p.

💡 V=43π×33=43π×27=36π113.1V = \frac{4}{3}\pi \times 3^3 = \frac{4}{3}\pi \times 27 = 36\pi ≈ 113.1cm3.{cm}^{3}.

Question 5

A cone has radius 5 cm and height 12 cm. Find the volume in cm3{cm}^{3} to 1 d.p.

💡 V=13π×52×12=13π×300=100π314.2V = \frac{1}{3}\pi \times 5^2 \times 12 = \frac{1}{3}\pi \times 300 = 100\pi ≈ 314.2cm3.{cm}^{3}.

Common mistakes

Watch for these when working through the lesson.

  • Forgetting the 13\frac{1}{3} in the cone formula: the formula is 13πr2h\frac{1}{3}\pi r^2 h, not πr2h\pi r^2 h.
  • Using diameter instead of radius: always check whether you've been given radius or diameter. If diameter, divide by 2 first.
  • Confusing units: if radius is in cm, the volume is in cm3{cm}^{3}. If radius is in metres, the volume is in m3{m}^{3}.

Related topics

These ideas fit closely with this lesson.

  • Surface area of cylinders, cones and spheres
  • Pythagoras' theorem in 3D
  • Density and volume

Practice next

Independent practice will plug in here

This lesson builds the understanding first. Deeper adaptive practice can sit here later.